To solve this, we use the formula for the volume of the frustum of a cone which is expressed as:
<span>V= (H/6)[WL + (W+a)(L+b) + ab]
</span>V = 3/6 [(6 ft. × 8 ft.) + (6 + 14)(18 + 8) + (<span>14 ft. × 18 ft.)]
</span>V = 409.98 ft^3 <-----OPTION C
V + 6 < 7
subtract 6 from both sides:-
V < 7 - 6
V < 1
3/6 = 24/48
3/4 = 36/48
3/8 = 18/48
3/8, 3/6, 3/4