Answer:
3 3/4= 3*4+3/4=15/4
1 7/9= 1*9+7=16/9
16/9*15/4= 4/3*5/1= 20/3 = 6 2/3
So y=mx+b form
m=slope=rise over run
b=y intercepe or where it crosses the y axis
so one way is to input values for x and get vales for y exg
if x=1 then y=-2
if x=2 then y=1
if x=0 then y=-5 so some points are
(x,y)
(1,2)
(2,1)
(0,-5)
(3,4)
then plot those points
(−∞,2)∪(−2,2)∪(2,∞)
{x|x≠2,−2}
When you have a bunch like this, I find it easiest to graph them.
The numbers of real solutions are ...
2
0
2
1
I know you know how to use Desmos to graph these. You can also write a little spreadsheet program to compute the discriminant b^2 -4ac, or do it the hard way.
1^2 -4(-3)(12) = 145 . . . positive, so 2 solutions
(-6)^2 -4(2)(5) = -4 . . .. negative, so 0 solutions
7^2 -4(1)(-11) = 93 . . . .. positive, so 2 solutions
(-8)^2 -4(-1)(-16) = 0 . .. zero, so 1 solution
Addition because it asks how much