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Radda [10]
3 years ago
11

Simplify the expression.

Mathematics
1 answer:
musickatia [10]3 years ago
6 0

4(10n² - 2) - 5(8n² + 7) =

= 40n² - 8 - 40n² - 35 =

= 40n² - 40n² - 8 - 35 = -43 ← the end

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In 1991, the moose population in a park was measured to be 1900. By 1997, the population was measured again to be 3600. If the p
LUCKY_DIMON [66]

Answer:

Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)

The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.

Step-by-step explanation:

.

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2 years ago
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1 year ago
I need these to be right dont throw out the wrong
kolezko [41]

Answer:

DIana for image 1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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