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docker41 [41]
2 years ago
15

On one afternoon in a shoe warehouse, three large shipments of shoes arrived. The weights of the shipments were 1 ton 115 pounds

, 1,723 pounds 7 ounces, and 957 pounds 11 ounces. What was the total weight of the three shipments?
Mathematics
1 answer:
Goryan [66]2 years ago
8 0

Alright, lets get started.

The weight of first shipment = 1 ton 115 pounds

As we know, 1 ton = 2000 pounds, so

So, the weight of first shipment = 2000 + 115 = 2115 pounds

The weight of second shipment = 1723 pounds 7 ounces

The weight of third shipment = 957 pounds 11 ounces

So, adding all three weights = 2115 pounds + 1723 pounds 7 ounces + 957 pounds 11 ounces

So, all three weights = 4795 pounds 18 ounces

As we know, 16 ounces = 1 pound, so

all three weights = 4795 pound 1 pound 2 ounces

All three weights = 4796 pounds 2 ounces

4796 could be wriiten as 4000 + 796

As we know, 2000 pound = 1 ton so

All three weight = 2 tons 796 pounds 2 ounces

So, the total weight of three shipments = 2 tons 796 pounds 2 ounces   :   Answer

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Answer:   \bold{\dfrac{7}{8}=87.5\%}

<u>Step-by-step explanation:</u>

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I will use the latter: 1 - P(all boys)

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1 - P(all\ boys) \quad = \quad 1-\dfrac{1}{8}\quad =\large\boxed{\dfrac{7}{8}}

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8%

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C + 6 &gt; 5c - 2<br>solved and proof​
Elena L [17]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

c < 2

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

c+6>5c - 2\\--------------\\\\\rightarrow5c - 2< c + 6 \leftarrow \text{Notice how the sides are switched.}\\\\\rightarrow 5c - c -2 < c - c + 6\\\\\rightarrow 4c -2 < 6\\\\\rightarrow 4c - 2 + 2 < 6 + 2\\\\\rightarrow 4c  < 8\\\\\rightarrow \frac{4c

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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