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otez555 [7]
2 years ago
6

Autumn had a math homework assignment each day last week. Each assignment had a different number of problems and took her a diff

erent amount of time to complete, as shown by the table below. Number of Problems Time to Complete (minutes) 8 16 15 30 22 44 29 58 36 72 What is Autumn's rate of change of time in minutes with respect to each math problem? A. 1 minute per problem B. 9 minutes per problem C. 2 minutes per problem D. 7 minutes per problem
Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
4 0

Answer:La respuesta es 2 minutos, entonces la respuesta es C.

Step-by-step explanation:

cluponka [151]2 years ago
3 0

Answer:

The answer is 2 minutes, so the answer is C.

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Number 8 please it will help a lot
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3 years ago
Read 2 more answers
(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
I need help guys plsss
malfutka [58]

Answer:

6. r = 21 cm

7. A = 155.5 m²

Step-by-step explanation:

7: Formula for arc length is;

S = (θ/360) × 2πr

We are given;

S = 51 cm

θ = 139°

Thus;

51 = (139/360) × 2π × r

Making r the subject;

r = (51 × 360)/(2π × 139)

r ≈ 21 cm

8) Area of sector is gotten from the formula;

A = (θ/360) × πr²

A = (220/360) × (π × 9²)

A = 155.5 m²

8 0
2 years ago
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