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poizon [28]
2 years ago
14

I need help guys plsss

Mathematics
1 answer:
malfutka [58]2 years ago
8 0

Answer:

6. r = 21 cm

7. A = 155.5 m²

Step-by-step explanation:

7: Formula for arc length is;

S = (θ/360) × 2πr

We are given;

S = 51 cm

θ = 139°

Thus;

51 = (139/360) × 2π × r

Making r the subject;

r = (51 × 360)/(2π × 139)

r ≈ 21 cm

8) Area of sector is gotten from the formula;

A = (θ/360) × πr²

A = (220/360) × (π × 9²)

A = 155.5 m²

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Anvisha [2.4K]
C2 + a2 +2 = b
Would be the new formula
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3 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
3 years ago
Math linear functions
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5 0
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morpeh [17]
1/3 and 3/8
First, you would need to find the lowest common multiple.
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7 0
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mylen [45]

Answer:A

Step-by-step explanation:

4 0
3 years ago
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