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Natalka [10]
3 years ago
8

Solve E = mc2 for c. A) c = E m B) c = m E C) c = + m E D) c = + E m

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

C=\sqrt{E/M}  

enjoy the rest of your day!

r-ruslan [8.4K]3 years ago
6 0

Answer:

d

Step-by-step explanation:

i just did it

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What are the zeros of the function f(x)=x^2-2x-15?
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To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
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What is 42cm per second converted to meters per min
BARSIC [14]

25.2 meters per minute

8 0
2 years ago
Which of the undefined terms is used to define the term parallel lines
scoundrel [369]
<span>x.line is the correct answer</span>
6 0
3 years ago
What is the image of point (4, 5) after a counterclockwise rotation of 270º about the origin?
andriy [413]
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.

Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.

A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>

Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
3 0
3 years ago
- 20 = 2(n − 3) Asswer ?
jonny [76]

Answer:

Step-by-step explanation:

-20=2(n-3)

-20=2*n-2*3

-20=2n-6

-20+6-2n

-14/2=n

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4 0
2 years ago
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