Implement a function named largerThanN that accepts three arguments: an array of type int, the size of the array of type int and
1 answer:
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Answer:
Step by step explanation along with code and output is provided below
Explanation:
#include<iostream>
using namespace std;
// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three
void print_seconds(int hours, int mints, int seconds)
{
int total_seconds= hours*3600 + mints*60 + seconds;
cout<<"Total seconds are: "<<total_seconds<<endl;
}
// test code
// user inputs hours, minutes and seconds and can also leave any of them by entering 0 that will not effect the program. Then function print_seconds is called to calculate and print the total seconds.
int main()
{
int h,m,s;
cout<<"enter hours if any or enter 0"<<endl;
cin>>h;
cout<<"enter mints if any or enter 0"<<endl;
cin>>m;
cout<<"enter seconds if any or enter 0"<<endl;
cin>>s;
print_seconds(h,m,s);
return 0;
}
Output:
enter hours if any or enter 0
2
enter mints if any or enter 0
25
enter seconds if any or enter 0
10
Total seconds are: 8710
