All categories

4 years ago

Help subtracting this mixed numbers 6 3/7-3 11/21

Mathematics

2 answers:

Rudiy274 years ago

4 0

6 3/7 ——-> 45/7 x 3/3 = 135/21
3 11/21 ——-> 64/21

135/21 - 64/21 = 71/21
= 3 8/21

ipn [44]4 years ago

3 0

Answer:

2 19/21 = 2.9048

Step-by-step explanation:

6 3/7 - 3 11/21 = 61/21

= 2 19/21

= 2.9047619

You might be interested in

When factoring 8x + 12y - 24, the biggest factor will be 4? True or False?

podryga [215]

True, the biggest factor will be 4 :)

3 0

3 years ago

Solve the compound inequality. y - 3 > 5 OR y + 3 < -2

il63 [147K]

Answer: y < -5 or y > 8

<u>Step-by-step explanation:</u>

$y-3>5\quad \text{or}\quad y+38\quad \text{or}\quad y\quad \ \$

Graph: ←---------o -1 8 o------------→

Interval Notation: (-∞, -5) ∪ (8, ∞)

4 0

3 years ago

What is the equation of the circle with center (1, −1) that passes through the point (5, 7)?

kykrilka [37]

Answer:

Option C $(x-1)^2+(y+1)^2=80$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance from the center of the circle to any point on the circumference of the circle is equal to the radius of the circle

we have

(1,-1) and (5,7)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$d=\sqrt{(7+1)^{2}+(5-1)^{2}}$

$d=\sqrt{(8)^{2}+(4)^{2}}$

$d=\sqrt{80}\ units$

step 2

Find the equation of the circle in center radius form

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

substitute

$(x-1)^2+(y+1)^2=(\sqrt{80})^2$

$(x-1)^2+(y+1)^2=80$

3 0

3 years ago

Which expression shows 20 + 24 with 2 as a factor of each term?

stira [4]

Answer:

2(10 + 12)

Step-by-step explanation:

20 + 24

=> 2(10 + 12)

Therefore, 2(10 + 12) is our expression with 2 as a factor for each term.

Hoped this helped.

8 0

2 years ago

16+24/8-6 is equal to________

Yuliya22 [10]

Answer: The answer is 28. Hope this helps:)

8 0

3 years ago

Read 2 more answers