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Aleksandr-060686 [28]
3 years ago
15

What is 119,000,003 in two forms

Mathematics
2 answers:
ratelena [41]3 years ago
6 0
One hundred thousand, nineteen million,three.
Helen [10]3 years ago
3 0
Expanded form: 100,000,000+ 10,000,000+9,000,000+3

written form: one hundred ninteen million and three.
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Write a percent that has a value between the two decimals 0.4 and 0.5
Juliette [100K]
A percent would be 0.45 
5 0
4 years ago
If the ratio of boys to girls at the school is 2:5 and there are 40 boys how many girls are there?
sukhopar [10]

Answer:

100 girls

Step-by-step explanation:

The ratio of boys : girls is 2 : 5.

In other words, boys are 2 parts of the school while girls are 5 parts of the school.

Since there are 40 boys, 2 parts of the school is 40. Thus:

2p = 40\\p = 20

1 part is 20.

Since there are 5 parts girls, there are

5p = 5*20 = 100

100 girls.

Answer: 100 girls

5 0
3 years ago
Pls help me Factor x^2−4x+4<br> thx
shusha [124]
Find the factors 
The factor is -2
Finally equation:
(x-2)(x-2)

8 0
3 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0
3 years ago
Solve the system of equations<br> -5x+13y+-7<br> 5x+4y=24<br> y=<br> x=
aleksklad [387]
<h3>The value of y is equal to 1.</h3><h3>The value of x is equal to 4.</h3>

Because both equations have a term that will cancel out if they're added together, we're going to add both equations together.

-5x + 5x = 0

13y + 4y = 17y

-7 + 24 = 17

17y = 17

Divide both sides by 17.

y = 1

Now that we have a constant value of y, we can solve for x.

-5x + 13(1) = -7

-5x + 13 = -7

Subtract 13 from both sides.

-5x = -20

Divide both sides by -5.

x = 4


3 0
3 years ago
Read 2 more answers
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