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Aleksandr-060686 [28]
3 years ago
15

What is 119,000,003 in two forms

Mathematics
2 answers:
ratelena [41]3 years ago
6 0
One hundred thousand, nineteen million,three.
Helen [10]3 years ago
3 0
Expanded form: 100,000,000+ 10,000,000+9,000,000+3

written form: one hundred ninteen million and three.
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Solve 3(x+1)=7(x-2)-3
tia_tia [17]

Answer:

x = 5

Step-by-step explanation:

To solve this, we just have to the multiplication and do the simplification (adding up the similar terms) afterwards:

3(x+1)=7(x-2)-3 becomes...

3x + 3 = 7x - 14 - 3

3x + 3 = 7x -17

Then we move all x's on one side and all plain numbers on the other side, we'll move the x's to the right since there's a bigger value there, and will move the plain numbers on the left side, by subtracting 3x and by adding 17 on both sides

3x + 3 - 3x + 17 = 7x -17 + 17 - 3x

20 = 4x

If we isolate x alone we have:

20/4 = x or x = 5

7 0
3 years ago
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A CD's sale price is $14. This is a 4% decrease from its original price. What was the original price?
atroni [7]

Answer:

0.56

Step-by-step explanation:

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3 years ago
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5. Naomi was watching a game show where
Solnce55 [7]

Answer:

C) 50

Step-by-step explanation:

This is because -10 x 5 = -50 and if you have 20 points to start with, you just do 20-(-30)=20 and two minuses make a plus so it is 20 + 30 which is 50.

8 0
3 years ago
Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim
sergejj [24]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958      

c) p_v =P(t_{34}>2.958)=0.0028    

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

The sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=17 represent the sample mean    

s=4 represent the sample standard deviation

n=35 sample size  

\mu_o =15 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

Since we don't  know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958  

Part c P-value  

The degrees of freedom are given by:

df = n-1= 35-1=34

Since is a right tailed test the p value would be:  

p_v =P(t_{34}>2.958)=0.0028  

Part d Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

7 0
3 years ago
Four posters cost $19.20. How many posters can you buy for $48.00?
stich3 [128]
You can buy 8 posters with 48.00 19.20x2=38.40 the leftover change isn’t enough to buy more
8 0
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