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sp2606 [1]
3 years ago
12

The circle on the right has center O. Its radius is 3 yd., and the central angle a measures 130°. What is the area of the shaded

region? Give the exact answer in terms of π, and be sure to include the correct unit in your answer.

Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

area of the sector = 3.25π yard²

Step-by-step explanation:

The radius of the circle is 3 yards . The central angle is 130° let us say it is the sector angle of the circle. The angle is 130°. If the shaded area of the circle is the sector area of the circle the area of the sector can be computed below.

area of a sector = ∅/360 × πr²

where

∅ = center angle

r = radius

area of the sector = 130/360 × π × 9

area of the sector = 1170π/360

area of the sector = 3.25π yard²

If the shaded area is segment. The shaded area can be solved with the formula.

Area of segment = area of sector - area of the triangle

Area of segment =  ∅/360 × πr² - 1/2 sin∅ r²

The picture demonstrate the area of sector and the segment of a circle with illustration on how to compute the area of the triangle

 

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Human blood may contain either or both of two antigens, A and B. Blood that contains only the A antigen is called type A, blood
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Answer:

A. 0.50

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C. 0.05

Step-by-step explanation:

A. Based on the initial statistics, 50% of the blood type is blood type O, hence the probability of choosing bold type O at random is 50/100, which is 0.50 to two decimal places.

B. The total number of donors that can donate to Blood type A is 85%, thus, the probability is 85/100, which is 0.85 to two decimal places.

C. The percentage of people that have the type AB blood is 5%, thus the probability of someone having the A antigen and blood type AB is 5/100, which is 0.05 to two decimal places.

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Step-by-step explanation:

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Solve the quadratic for x, then enter the numerical value of your solution. (If there are two solutions, either one will work.)
xz_007 [3.2K]

Answer: X= -1 OR X= 11

Step-by-step explanation:

Step 1 : Equate ( x-5)² since it occurred twice, hence the reason 2 is added in front of (x-5)²

= (x-5)²

= (x-5)(x-5)

= (x²-5x-5x+25)

= (x²-10x+25)

Step 2: multiply the result by two since it occurs twice and also bring the equation

= 2 (x²-10x+25) +7 = 79

= 2x²- 20x+50+7 = 79

= 2x²- 20x+57 =79

Step 3: most quadratic equation are always equal to zero, let's make this one equal to Zero by subtracting 79 from both sides

= 2x²-20x+57-79 = 79-79

= 2x²-20x-22=0

Step 4: divide the equation by a common number to get the least coefficient of the three coefficients

Dividing the three by 2

(2x²-20x-22)/2 = x²- 10x- 11

Step 5: Factorise completely

Sub step 1 : the first term in the equation is X² which makes the first term coefficient 1; the second term in the equation is -10x which makes the second term coefficient -10, the constant has a coefficient of -11

Sub step 2: multiply the coefficient of the first term (1) and the constant (-11) which gives us (-11)

1*-11 = -11

Sub step 3: Get two numbers in such a way that the addition of the first number and the second number gives the second coefficient in the quadratic equation and the multiplication of the two numbers will give us the product of the first coefficient and the constant.

And the two numbers is +1 and -11, the sum of the two numbers will give us -10 and the product will give us -11.

Step 6: slot the two numbers (+1, -11) into the equation by making themr replace the second coefficient

x²-10x-11=0

= x²+x-11x-11 =0

Step 7: split the equation into two and Factorise further

= (x²+x)(-11x-11) =0

= x(x+1)-11(x+1) = 0

= x+1= 0 or x-11 =0

Step 8 split them into individual equation

= x+1= 0.

Subtract 1 from both sides

= X+1-1=0-1

= x= -1

Or X should be

= x-11=0

Add 11 to both sides

= X-11+11 = 0+11

= x= 11

6 0
3 years ago
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