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vaieri [72.5K]
3 years ago
9

A train is moving at a speed of 50 km/h. How many hours will it take the train to travel 600 kilometers?

Physics
2 answers:
EastWind [94]3 years ago
6 0

Answer:

12 hours

Explanation:

600 divided by 50 is 12

Ad libitum [116K]3 years ago
5 0

Answer: 12 hours

Explanation: you divide 600 by 50 to know how many hours it will take to get to 600 kilometers

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Can a body moving at constant speed have acceleration ?​
otez555 [7]

  • <em><u>it can be safely concluded that an object moving in a circle at constant speed is indeed accelerating. It is accelerating because the direction of the velocity vector is changing.</u></em>

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>!</u></em></h2>

6 0
2 years ago
Which represents a type of electromagnetic wave? A. slinky wave B. jump rope wave C. shortwave radio waves D. ocean wave
Dahasolnce [82]
The only item on that list that's an electromagnetic wave
is C). shortwave radio waves.
8 0
3 years ago
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Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi
nirvana33 [79]

Answer:

a) F = 882.63\,N, b) \dot W= 4413.15\,W, c) \eta = 15.216\,\%.

Explanation:

a) Let assume that car travel on a horizontal surface. The equations of equilibrium of the car are:

\Sigma F_{x} = F - \mu_{r}\cdot N = 0

\Sigma F_{y} = N - m\cdot g = 0

After some algebraic handling, the following expression for the propulsion force is constructed:

F = \mu_{r}\cdot m \cdot g

F = (0.06)\cdot (1500\,kg)\cdot (9.807\,\frac{m}{s^{2}} )

F = 882.63\,N

b) The power require to move the car at a speed of 5 meters per second is:

\dot W = F\cdot v

\dot W = (882.63\,N)\cdot (5\,\frac{m}{s} )

\dot W= 4413.15\,W

c) The efficiency of the car is:

\eta = \frac{(882.63\,N)\cdot (15\,mi)\cdot (\frac{1609\,m}{1\,mi} )}{(1.4\times 10^{8}\,J)} \times 100\,\%

\eta = 15.216\,\%

3 0
3 years ago
A 20-cm-long spring is attached to a wall. When pulled horizontally with a force of 100 N, the spring stretches to a length of 2
Delvig [45]

Answer:

the length of stretched spring  in cm is 22

Explanation:

given information:

spring length, x1 = 20 cm = 0.2 m

force, F = 100 N

the length of spring streches, x2 = 22 cm = 0.22 m

According to Hooke's law

F = - kΔx

k = F/*=(x2-x1)

  = 100/(0.22 - 0.20)

  = 5000 N/m

if the spring is now suspended from a hook and a 10.2-kg block is attached to the bottom end

m = 10.2 kg

W = m g

    = 10.2 x 9.8

    = 99.96 N

F = - k Δx

Δx = F / k

     = 99.96 / 5000

     = 0.02

Δx = x2- x1

x2 = Δx + x1

    = 0.20 + 0.02

    = 0.22 m

     = 22 cm

7 0
3 years ago
A truck is traveling east at 80 km/h. At an intersection 32 km ahead, a car is traveling north at 50 km/h. How long after this m
nirvana33 [79]

The time elapsed when the vehicles are closest to each other is 20 min.

The given parameters:

  • Speed of the truck, u = 80 km/h
  • Distance, d = 32 km
  • Speed of the car, v = 50 km/h

<h3>Principles of relative speed</h3>

The time elapsed when the cars are close to each other is calculated by applying the principles of relative speed.

(V_r) t = d\\\\V_r^2 = 50^2 + 80^2\\\\V_r =\sqrt{50^2 + 80^2} \\\\V_r = 94.34 \ km/h

94.34 t = 32\\\\t = \frac{32}{94.34} \\\\t = 0.34 \ hr\\\\t \approx 20 \min

Thus, the time elapsed when the vehicles are closest to each other is 20 min.

Learn more about relative velocity here: brainly.com/question/24430414

3 0
2 years ago
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