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emmainna [20.7K]
3 years ago
15

what is the kinetic energy of a 0.50 g insect traveling in a straight line at 5.0m/s? a)6.25J b) 1.25J

Physics
1 answer:
TiliK225 [7]3 years ago
8 0
Kinetic energy = 0.5 × mass × speed^2

Ek = 0.5 × 0.50 × 5^2

Ek = 6.25J
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Given that two vectors A = 5i-7j-3k, B = -4i+4j-8k find A×B​
WARRIOR [948]

\textbf{A}×\textbf{B}= 68\hat{\textbf{i}} + 52\hat{\textbf{j}} - 8\hat{\textbf{k}}

Explanation:

Given:

\textbf{A} = 5\hat{\textbf{i}} - 7\hat{\textbf{j}} - 3\hat{\textbf{k}}

\textbf{B} = -4\hat{\textbf{i}} + 4\hat{\textbf{j}} - 8\hat{\textbf{k}}

The cross product \textbf{A}×\textbf{B} is given by

\textbf{A}×\textbf{B} = \left|\begin{array}{ccc}\hat{\textbf{i}} & \hat{\textbf{j}} & \hat{\textbf{k}} \\\:\:5 & -7 & -3 \\ -4 & \:\:4 & -8 \\ \end{array}\right|

=  \left|\begin{array}{cc}-7 & -3\\\:4 & -8\\ \end{array}\right|\:\hat{\textbf{i}}\:+\:\left|\begin{array}{cc}-3 & \:\:5\\-8 & -4\\ \end{array}\right|\:\hat{\textbf{j}}\:+\: \left|\begin{array}{cc}\:\:5 & -7\\-4 & \:\:4\\ \end{array}\right|\:\hat{\textbf{k}}

= 68\hat{\textbf{i}} + 52\hat{\textbf{j}} - 8\hat{\textbf{k}}

5 0
3 years ago
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2
Vlad1618 [11]

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

8 0
3 years ago
When steam condenses
9966 [12]
A is the correct answer
3 0
3 years ago
Read 2 more answers
Pls answer the 15a answer i cant understand it​
Maksim231197 [3]

Materials required for the experiment of limiting force borne by string:-

  1. String balance
  2. weights
  3. light strings
  4. weight hanger
  5. pan for spring balance
  6. Sand

Steps of procedure for for the experiment of limiting force borne by string:-

  1. First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.
  2. Add additional weight to the hanger again and again. And continue the same until the string is broken.
  3. Note down the weight (x) where the string is broken.
  4. Suspend spring balance to a support.
  5. Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.
  6. Now place the weights (x-100 grams) in pan.
  7. Observe the reading in the spring balance.
  8. Add a small amount of sand in the pan by observing the readings.
  9. same is to be done till the string is broken.

Learn more about limiting force here:- brainly.com/question/11371672

#SPJ1

6 0
1 year ago
How are metal bridges built to cope with changes of temperature?
nirvana33 [79]
As the metal expands as does the road bed so neither really effevts those foing over the bridge. as it is hot the metal will expand and so will most tarmac on roads.
8 0
3 years ago
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