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2 years ago

Question 20 (4 points)

Physics

1 answer:

irinina [24]2 years ago

3 0

Explanation:

C is correct.

Newton second law states that force is directly proportional to acceleration with m being the constant of variation.

$f _{net} = m(a)$

$250 = 50(a)$

$a = 5$

A is wrong, the constant g only happens in free fall or in vertical direction

B and D are wrong due to the mathematical error or equation error

You might be interested in

Calculate the de Broglie wavelength of (a) a mass of 1.0 g traveling at 1.0 m s−1 , (b) the same, traveling at 1.00 × 105 km s−1

lesantik [10]

Answer:

a) $\lambda=6.63\times10^{-31}m$

b) $\lambda=6.63\times10^{-39}m$

c) $\lambda=9.97\times10^{-11}m$

d) $\lambda=4.03\times10^{-36}$ m

e)λ=∞

Explanation:

De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:

$\lambda=\frac{h}{P}=\frac{h}{mv}$

with h the Plank's constant ( $6.63\times10^{-34}\frac{m^{2}kg}{s}$ ) and P the momentum of the object that is mass (m) times velocity (v).

a) $\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}kg*1.0)}$

$\lambda=6.63\times10^{-31}m$

b) $\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}*(1.00\times10^{8}))}$

$\lambda=6.63\times10^{-39}m$

c) $\lambda=\frac{6.63\times10^{-34}}{(6.65\times10^{-27}*1000)}$

$\lambda=9.97\times10^{-11}m$

d) $\lambda=\frac{6.63\times10^{-34}}{(74*2.22)}$

$\lambda=4.03\times10^{-36}$ m

e) $\lambda=\frac{6.63\times10^{-34}}{(74*0)}$

λ=∞

6 0

3 years ago

If you drive at 100 km/hr for six hours how far will you go

zhuklara [117]

600km/h

100 times 6 = 600

8 0

3 years ago

A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i

Darya [45]

The position of the first ball is

$y_1=h-\dfrac g2t^2$

while the position of the second ball, thrown with initial velocity $v$ , is

$y_2=vt-\dfrac g2t^2$

The time it takes for the first ball to reach the halfway point satisfies

$\dfrac h2=h-\dfrac g2t^2$

$\implies\dfrac h2=\dfrac g2t^2$

$\implies t=\sqrt{\dfrac hg}$

We want the second ball to reach the same height at the same time, so that

$\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2$

$\implies h=2v\sqrt{\dfrac hg}-g\left(\dfrac hg\right)$

$\implies h=v\sqrt{\dfrac hg}$

$\implies v=\sqrt{hg}$

8 0

4 years ago

The center of mass of the system is the point at which the total mass of the system could be concentrated without changing the _

Sveta_85 [38]

The centre of mass of the system is the point at which the total

mass of system could be concentrated without changing the moment

of the system.

Centre of Mass is the point at which the whole mass of the system

is assumed to be concentrated.

The general formula for the COM is:

xₙ = Σmₐxₐ / Σmₐ where, a = 1,2,3.........n

Here the term Σ mₐ xₐ is called the first moment of the system and the

denominator expression is called total mass of the system.

Therefore, from this theory we can say that the moment of the system

remain unchanged while calculating the COM.

Hence, The centre of mass of the system is the point at which the total

mass of system could be concentrated without changing the moment

of the system.

learn more about centre of mass here:

brainly.com/question/3454419

#SPJ4

8 0

2 years ago

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/. To determine the depth of

leva [86]

Answer;

=32.15 meters

Explanation;

Use the formula

s= ut+ 0.5 a (t)^2 to find out 's'

where s= distance traveled

u=initial velocity which is zero in this case

t= time taken to travel 's' distance

a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )

Therefore;

S = 0.5 * 1.62 * 6.3 * 6.3

= 32.1489 meters

Thus; the crater is 32.15 meters deep.

3 0

3 years ago