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iogann1982 [59]
3 years ago
6

30 points plus brainliest for best answer no funny answers Assignment: Waves Concept Map Exploration Your concept map will compa

re the manner in which energy is transferred by mechanical waves and electromagnetic waves. Include the following somewhere in your concept map: • types of energy transferred • medium required (if applicable) for transfer of energy • speed of energy transfer through various mediums (solid, liquid, gas) Concept Idea Bank: mechanical waves transfer light energy can pass through matter electromagnetic waves do not require a medium transfer sound energy require a medium travel is slowed as density of travel is faster as density of matter increases matter increases 1. Think about the kind of map that would be best to use to organize and compare mechanical and electromagnetic waves. 2. Review the rubric that will be used to grade this assignment. 3. Create your concept map. 4. When you have completed the concept map, don’t forget to submit it for a grade. Describe the functional relationship between the two quantities in the graph.

Physics
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

Waves: "The phenomenon in which any number of particles or the energy packets that originates from a transmitter  travels in a direction and it is somehow directed towards a receiver end is called as waves."

Electromagnetic wave: The type of waves which do not require any sort of medium for the transformation process of the energy, as it is directed towards from a transmitter towards a receiver.

For example: Radio, IR , Ultra sonic waves etc.

Mechanical waves: The type of waves which requires some medium to transfer the energy packets from one place to another, or from one point to the other using some medium. As the medium can be solids,liquids, or any gaseous forms.

For example: Sound waves, seismic waves etc.

Explanation:

The transfer of energy in Mechanical waves and Electromagnetic waves:

Both, the waves are much different due ones basic requirement of a medium while the other don't require one. As the density of any medium if increased it will increase the speed of the wave propagation. And this any medium being more denser will result in high speed form mechanical waves.

While, the electromagnetic waves can pass through matters or elements easily with out having any obstruction faced in its path because presence of medium is no requirement for the wave propagation.

I hope this helps!!

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marin [14]
The answer is gravitational:)
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3 years ago
The angular velocity of a process control motor is (13−12t2) rad/s, where t is in seconds. Part A At what time does the motor re
mihalych1998 [28]

Answer:

Explanation:

Given

\omega =13-\frac{1}{2}\cdot t^2

Motor reverse its direction when \omega =0

13-0.5t^2=0

26=t^2

t=\sqrt{26}=5.099\approx 5.1 s

(b)

\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

\int d\theta =\int_{0}^{5.1}\omega dt

\int d\theta =\int_{0}^{t}(13-.05t^2)dt

\theta =(13t-0.1667\times t^3)_0^{5.1}

\theta =44.192^{\circ}

4 0
3 years ago
A 37-cm-long wire of linear density 18 g/m vibrating at its second mode, excites the third vibrational mode of a tube of length
lora16 [44]

Answer:

T = 4.42 10⁴ N

Explanation:

this is a problem of standing waves, let's start with the open tube, to calculate the wavelength

        λ = 4L / n                 n = 1, 3, 5, ...    (2n-1)

How the third resonance is excited

       m = 3

       L = 192 cm = 1.92 m

       λ = 4 1.92 / 3

       λ = 2.56 m

As in the resonant processes, the frequency is maintained until you look for the frequency in this tube, with the speed ratio

      v = λ f

      f = v / λ

      f = 343 / 2.56

      f = 133.98 Hz

       

Now he works with the rope, which oscillates in its second mode m = 2 and has a length of L = 37 cm = 0.37 m

The expression for standing waves on a string is

           λ = 2L / n

           λ = 2 0.37 / 2

           λ = 0.37 m

The speed of the wave is

          v = λ f

As we have some resonance processes between the string and the tube the frequency is the same

          v = 0.37 133.98

          v = 49.57 m / s

Let's use the relationship of the speed of the wave with the properties of the string

              v = √ T /μ

              T = v² μ

              T = 49.57²   18

              T = 4.42 10⁴ N

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