The gravitational potential energy of the rock is:
490 J at 50 m
196 J at 20 m
9.8 J at 1 m
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field.
For an object near the Earth's surface, the GPE is given by
where
m is the mass of the object
is the acceleration of gravity at Earth's surface
h is the heigth of the object relative to the ground
For the rock in this problem,
m = 1 kg
So its GPE at h = 50 m is
The GPE at h = 20 m is
While the GPE at h = 1 m is
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Answer:
Explanation:
To get the person Moving you have to overcome the static (means not moving) friction coefficient. U(static)
To get the person going at the same speed you have to overcome the kinetic friction coefficient. U(Kinetic)
Force to get him moving is 198 N. Force = ma = U(static)Mg
combining the 2 equations you get 198N = U(static)* 55kg *9.8m/s^2 Solve for U(static)
Same equation to keep him moving except with the dynamic force and the dynamic U
175N= U(kinetic)*55kg*9.8m/s^2 Solve (U dynamic)
Given,
Mass of the ball (m) = 1.50 x 10³ kg = 1500 kg
Height raised = Displacement of the ball (D) = 40.0 m
Time taken (t) = 20 seconds
Power = Work done(W) ÷ time taken (t)
Work done (W) = Force (F) x Displacement (D)
Force (F) = Mass (m) x Acceleration due to gravity (g)
Acceleration due to gravity for earth (g) = 9.81 m/s²
Therefore,
Force (F) = 1500 x 9.8 = 14715 N
Work done = Force x Displacement = 14715 x 40 = 588600 Joules
Now,
Power = Work done ÷ time taken = 588600 ÷ 20 = 29430 Watts
Answer:
I think its dense and solid and located near a star.
Explanation:
Hope this helps, good luck.
Answer:
there are 2188 people at the game
Explanation:
Given the data in the question;
we know that decibel is defined as; dB = 10log(l/l₀)
so if one produces an intensity l₁, it results in 69.6 dB
69.6 = 10log(l₁/l₀) ---- equ1
also. if x number of people produces this intensity, it result to 103 dB
103 = 10log(xl₁/l₀)
103 = 10( log(l₁/l₀) + log(x) )
103 = 10log(l₁/l₀) + 10log(x) ----- equ2
input equation 1 into to equation 2
103 = 69.6 + 10log(x)
10log(x) = 103 - 69.6
10log(x) = 33.4
divide both side by 10
log(x) = 3.34
x =
x = 2187.76 ≈ 2188
Therefore, there are 2188 people at the game