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3 years ago

Verify if this is an identity cot(-x) tanx=-1

1 answer:

7 0

hello :
cot(-x) tan(x)=-1......(*)
* cot(x) = 1/tan(x)
cot(-x) = -cot(x)= -(1/tan(x))

cot(-x) tan(x) = -(1/tan(x))×tan(x)=-1

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The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the fir

xxMikexx [17]

Answer:

common difference is 0.5

first term is 5

Step-by-step explanation:

use the formula for the nth term of an ap Tn=a+(n-1)d

T12=10.5

T18=13.5

therefore come up with two equations

T12=a+(12-1)d

10.5=a+11d(1st equation)

T18=a+(18-1)d

13.5=a+17d(2nd equation)

then solve both as a simultaneous equation

a+11d=10.5

a+17d=13.5

-6d/-6=-3/-6

d=0.5

use one of the equations to find the first term

a+11(0.5)=10.5

a+5.5=10.5

a=10.5-5.5

a=5

I hope this helps

please mark as brainliest

7 0

3 years ago

Mike played a game and earned 25 points if he then lost 30 points what was his final score?

Vlad1618 [11]

Answer:

Step-by-step explanation:

I subtracted

4 0

2 years ago

Read 2 more answers

Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and

SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

$f(x)=\left\{\begin{array}{l}x+9,\ \ x$

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For $x$

$\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18$

2. For $x\ge 9:$

$\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18$

So, limit exists and is equal to 18.

8 0

3 years ago

Place the correct symbol, < or >, between the two numbers 11/18 17/24

evablogger [386]

For this case we must indicate the correct sign between the following numbers:

$\frac {11} {18}\ and\ \frac {17} {24}$

We have to:

$\frac {11} {18} = 0.611111111111\\\frac {17} {24} = 0.708333333333$

So, we have to $\frac {17} {24}> \frac {11} {18}$

Answer:

$\frac {17} {24}> \frac {11} {18}$

5 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mila [183]

Answer:

$m\angle H = 44.4\°$ .

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7 ....Side opposite to angle H

GH = 10 .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

$sin \ H = \frac{Oppsite\ side\ to\ \angle H}{Hypotenuse}$

Substituting the values we get;

$sin\ H = \frac{7}{10} = 0.7$

Now taking $sin^{-1}$ we get;

$\angle H = sin^{-1}\ 0.7 = 44.427$

rounding to nearest tenth we get.

$m\angle H = 44.4\°$ .

Hence $m\angle H = 44.4\°$ .

6 0

3 years ago