Take a look at the diagram below.
This problem looks like a great candidate for using the Law of Cosines.
If you know two sides, you can find the third side from the angle opposite or vice versa. Should the sides be a, b, and c, and their opp. angles A, B, and C...
a² + b² - 2ab(cosC) = c²
Let's plug in what we know...a = 55, b = 25, and m<C = 25".
55² + 25² - 2(55)(25)(cos(25")) = c²
One thing to note is that our angle measure is in <em />seconds. Unless you're using Google's built in calculator, you'll wind up having to convert to degrees. 60 seconds in a minute, 60 minutes in a degree...blahblahblah.
Anyways, cos(25") comes out to be practically 1. (0.99999993)
Let's get evaluating.
3025 + 625 - 2750(1) = c²
3025 + 625 - 2750 = c²
900 = c²
30 = cThe tree is
30 meters from the fence post.
3s + 2p = 85.50....multiply by -1
3s + 4p = 123
--------------------
-3s - 2p = -85.50 (result of multiplying by -1)
3s + 4p = 123
--------------------add
2p = 37.50
p = 37.50/2
p = 18.75 <=== cost of the pants
3s + 4p = 123
3s + 4(18.75) = 123
3s + 75 = 123
3s = 123 - 75
3s = 48
s = 48/3
s = 16 <=== cost of each shirt
Answer:
-4 < n ≤ 5
Step-by-step explanation:
_________________
Hi,
f°g means : apply first g then f . so calculate "g" and then use result as "x" in f.
g°f means : you apply first f then g
so : f°g = 2(3x²-x) -5 = 6x²-2x- 5
To improve in math, you need practice. have a try with g°f :)
give the answer in comments, and I will tell you if you are correct.
good luck.
Answer: (-∞, 2)∪(2, 3]∪(4, ∞)
Step-by-step explanation:
Domain is the allowed x values in the function. The numerator, x + 1 will be defined for all numbers. But that fraction wont be, the minute that fractions denominator is equal to zero, your entire function becomes undefined.
So lets figure out what number will make this undefined. Then we'll know the functions domain is everywhere but that x value.
Make x^2 - 6x + 8 = 0
What two numbers multiply to equal +8 but add to equal -6? Thats -4 and -2.
(x - 4)(x - 2) = 0 This means the function is undefined when x equals 4 and 2
(-∞, 2)∪(2, 3]∪(4, ∞)