Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
Answer:
c
Step-by-step explanation:
cuz ik
Answer:
you can't find the square root of a negative
Step-by-step explanation:
Answer:
-x^3*(x + 1)
Step-by-step explanation:
Perform the indicated multiplication and then write out all the terms in descending order by powers of x:
-x^3(5x+1)+4x^4 = -5x^4 - x^3 + 4x^4
= -x^4 - x^3, or = -x^3*(x + 1)
Answer:
A
Step-by-step explanation:
Given
y = 2x² - 3x + 1
To find the zeros let y = 0, that is
2x² - 3x + 1 = 0
Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × 1 = 2 and sum = - 3
The factors are - 2 and - 1
Use these factors to split the x- term
2x² - 2x - x + 1 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) - 1(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x - 1) = 0
Equate each factor to zero and solve for x
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = 
x - 1 = 0 ⇒ x = 1
