Answer:
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 7.2 minutes and a standard deviation of 2.1 minutes.
This means that
For a randomly received emergency call, find the probability that the response time is between 3 and 9 minutes.
This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3.
X = 9
has a pvalue of 0.8051
X = 3
has a pvalue of 0.0228
0.8051 - 0.0228 = 0.7823
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
Answer:
volume = 1583.36 rounded to the nearest tenth is 158.4
Step-by-step explanation:
V = π * r^2 * v = π · 6^2 · 14 ≈ 1583.3627
please give me brainliest
To solve this you just move the letters and numbers around until you get a different equation that is the same as the original equation.
You can also rule out the last two answers because they don’t have all the values.
P = pie
s=2prh can be written as s/2ph=r if we divide s by 2ph because we need to isolate r because all the answers have r isolated.
So the answer would be b s/2ph=r
Sorry that’s really badly worded and confusing, but I hope it helps.
10 of 1/6 (10 times 1/6) is 1 4/65 or 1 2/3 simplified. 5 of 1/3 (5 times 1/3) is
1 2/3
Answer:
the standard form of a linear equation required is B must be positive