You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Its C)126in I think because top base is 16, bottom base is 12 and the height is 9.
Answer:
She deposits $17.00 each week
Step-by-step explanation:
You multiply 85 times 0.2 which gives you 17.
Step 1: set equations equal to eachother
2x+2=x-1
which equals to x=-3
so the answer is one.
