Either I don't understand the question fully or this has a whole lot of answers.
For example, if all the numbers were 12 there would be an average of 12 and would equal 96 as the sum
Find value of determinant.
The determinant is a term that is inside a square root and part of the quadratic formula used for solving quadratic equations.
Let determinant be 'd'.
If d >0, Then there are 2 real solutions
If d = 0, Then there is only 1 real solutions
If d < 0, Then there are 0 real solutions but 2 imaginary solutions
d = b^2 - 4ac
For this problem, the coefficients are:
a = 1, b = -3, c = 8
d = (-3)^2 - 4(1)(8)
d = 9 -32 = -23
d is less than 0, therefore there are 0 real solutions and 2 imaginary solutions.
This is true because you cannot take square root of a negative number.
Answer:
4
Step-by-step explanation:
Another way to write this is 8/1 x 1/2. Then the answer would be 8/2. Simplify to get 4.
Answer: 0.00000565
Step-by-step explanation:
Required to win:
6 number match $10,000
5 number match $ 5,000
4 number match $ 1000
3 number match $ 5,00
2 number match $ 50
1 number match $ 10
Therefore, to win $10,000 ;
All 6 numbers must match
Number of right numbers = 6
Total numbers = 25
Since it is without replacement :
Probability = required outcomes / Total possible outcomes
P(First number match) = 6/25
P(second number match) = 5/24
P(third number match) = 4/23
P(fourth number match) = 3/22
P(fifth number match) = 2/21
P(sixth number match) = 1 / 20
Therefore, Probability of winning $10000 :
(6/25) * (5/24) * (4/23) * (3/22) * (2/21) * (1/20) = 720 / 127512000 = 0.0000056465
= 0.00000565
Answer:
Step-by-step explanation:
