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3 years ago

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Common denominator and strategy 2/3 and 10/15

2 answers:

inessss [21]3 years ago

8 0

The common denominator of 2/3 and 10/15 is 15.
To go further,
2/3 can be multipled by 5.
So 2 • 5 = 10
And 5 • 3 = 15
Therefore the new fraction is 10/15
When comparing to the 10/15, both of them are equivalent fractions.

Tom [10]3 years ago

3 0

Their common denominator is 15. Hope it helps! :) If you could vote my answer as the brainliest, that would be awesome! :)

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bulgar [2K]

Answer:

1

Step-by-step explanation:

Given

- 2y - 3x ← substitute x = 1 and y = - 2 into the expression

= - 2(- 2) - 3(1)

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3 years ago

A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.

fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

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$\theta = \arctan 0.1 \approx 5.711^\circ$

Answer: (a) 6 degrees

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$\sin\theta = \dfrac h c$

$h = c \sin \theta$

We could just take the sine of the angle we got but let's get it from the tangent exactly.

$\cos^2 \theta + \sin ^2 \theta = 1$

Dividing by squared cosine

$1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)$

$(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)$

$\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)$

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3 years ago

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nirvana33 [79]

Answer:

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Step-by-step explanation:

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so sin(30)= 7/a

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Hope its right

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3 years ago

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Alex73 [517]

see the picture attached to better understand the problem

we know that

two tangent segments drawn from the same exterior point are congruent

so

JA=JB ,

LA=LC,

KC=KB

JA=13 units

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kC=10 units

hence

perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units

therefore

the answer is

the perimeter of triangle JKL is 60 units

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Answer:

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