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3 years ago

10

Y=2/3x-4 y=-2x+4what is the solution

1 answer:

Radda [10]3 years ago

7 0

Answer:

$y=\frac{2}{3}x-4\\y=-2x+4$

Solution is (3,-2)

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What is the equation in slope-intercept form of the line that passes through the points ( -4, 47) and ( 2 , -16)?

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3 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

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3 years ago