The volume of liquid in a beaker decreases at a rate of 3.25 mL/h. What is the change in the volume of the liquid in the beaker
2 answers:
You might be interested in
Answer: Any real number x as long as and
In other words, anything but 0 or -2/3 is valid.
========================================================
Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Answer: 12.10
Step-by-step explanation:
Given : Mean :
Standard deviation :
The formula to calculate the z-score :-
For x= 5 degrees
For x= 10 degrees
The P-value :
In percent ,
Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%