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3 years ago

Which of the following is the correct representation of the polynomial

Mathematics

1 answer:

BARSIC [14]3 years ago

5 0

I believe the answer is B

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The probability of an event is 3/10 . What are the odds of the same event?

kozerog [31]

Answer:

D. $\frac{3}{7}$

Step-by-step explanation:

We have been given that the probability of an event is 3/10.

To find the odds of the same event we will use formula:

$\text{Odds of an event}=\frac{\text{Probability of the event}}{\text{1-Probability of the event}}$

$\text{Odds of the event}=\frac{\frac{3}{10}}{1-\frac{3}{10}}$

$\text{Odds of the event}=\frac{\frac{3}{10}}{\frac{1*10}{10}-\frac{3}{10}}$

$\text{Odds of the event}=\frac{\frac{3}{10}}{\frac{10-3}{10}}$

$\text{Odds of the event}=\frac{\frac{3}{10}}{\frac{7}{10}}$

Dividing a fraction with another fraction is same as multiplying the 1st fraction by the reciprocal of second fraction.

$\text{Odds of the event}=\frac{3}{10}\times \frac{10}{7}$

$\text{Odds of the event}=\frac{3}{7}$

Therefore, the odds of the same event is $\frac{3}{7}$ and option D is the correct choice.

8 0

3 years ago

-0.5(4a-1.5)+0.5a can someone help me out with this

taurus [48]

Answer:

Ygggg

Step-by-step explanation:

Gggt

5 0

2 years ago

This is another 2 in one so tell me which one is the answer to which question if you only answer one

Dominik [7]

Answer:

14 is 62.5 and 15 is 156

Step-by-step explanation:

5 0

3 years ago

An apartment building has 20 two-bedroom apartments and 8 three-bedroom apartments. If 4 apartments are chosen at random to be r

seraphim [82]

The answer is 4 of 28. i think so

7 0

3 years ago

Read 2 more answers

Find y'' by implicit differentiation. 4x^3 + 5y^3 = 4

iVinArrow [24]

$\bf 4x^3+5y^3=4\implies 12x^2+15y^2\cfrac{dy}{dx}=0\implies 4x^2+5y^2\cfrac{dy}{dx}=0
\\\\\\
5y^2\cfrac{dy}{dx}=-4x^2\implies \boxed{\cfrac{dy}{dx}=\cfrac{-4x^2}{5y^2}}\\\\
-------------------------------\\\\
\cfrac{d^2y}{dx^2}=\stackrel{quotient~rule}{\cfrac{-8x(5y^2)~~-~~(-4x^2)(10y)\left( \frac{dy}{dx} \right)}{(5y^2)^2}}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}$

$\bf \cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2-\frac{160x^4y}{5y^2}}{25y^4}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{\frac{-200xy^4-160x^4y}{5y^2}}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{(25y^4)(5y^2)}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{125y^6}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^4-32x^4y}{25y^6}$

6 0

3 years ago