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notka56 [123]
3 years ago
15

Nate's classroom has three tables of different lengths. One has a length of 4 1/2 feet, another has a length of 4 feet, and a th

ird has a length of 2 1/2 feet. What is the length of all three tables when pushed end to end?
Mathematics
2 answers:
Maru [420]3 years ago
7 0

Answer:

11\ ft

Step-by-step explanation:

we have

4\frac{1}{2}\ ft

4\ ft

2\frac{1}{2}\ ft

we know that

The length of all three tables when pushed end to end is the sum of the three lengths

Convert mixed number to an improper fraction

4\frac{1}{2}\ ft=\frac{4*2+1}{2}=\frac{9}{2}\ ft

2\frac{1}{2}\ ft=\frac{2*2+1}{2}=\frac{5}{2}\ ft

therefore

\frac{9}{2}\ ft+4\ ft+\frac{5}{2}\ ft

Rewrite 4\ ft as \frac{8}{2}\ ft

so

\frac{9}{2}\ ft+\frac{8}{2}\ ft+\frac{5}{2}\ ft=\frac{22}{2}\ ft=11\ ft

Anarel [89]3 years ago
6 0
<u><em>12 feet.
</em></u>
<u><em /></u><em />4 1/2= 4.5 
<u><em /></u><u><em /></u><em />4 1/2+ 4= 9.5 + 2.5 = 12
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The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


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