4/5 1/2 0.2 0.5 and apparently theres a character limit
Please take 1 minute, and really read the example solution
under problem #12. All of the other eight problems on the
sheet are solved in exactly the same way:
Multiply each side of the equation by the denominator of
the fraction ... the number under the variable (the letter).
This easy step will get you the answer to each of the
eight problems.
I can't help noticing that the title of the sheet is 'extra PRACTICE' .
If someone handed you the answers, then you would not get the
practice. That would be just like stealing from you, and would be
just plain mean.
Answer:
15.4919333848
Step-by-step explanation:
Evaluate : 8 - 9 + (-2)
8-9= -1 (because if you take away 9 from 8, you will end up with a negative number since there isn’t enough to take away.)
-1 + -2 = -3 (this is because when you are adding two negative numbers together, you will basically just add -1 and -2 as you would normally, then you would transfer the negative sign as well to make it -3)
Finally, your answer to this question is -3.
Subtract 1111 from both sides
5{e}^{{4}^{x}}=22-115e4x=22−11
Simplify 22-1122−11 to 1111
5{e}^{{4}^{x}}=115e4x=11
Divide both sides by 55
{e}^{{4}^{x}}=\frac{11}{5}e4x=511
Use Definition of Natural Logarithm: {e}^{y}=xey=x if and only if \ln{x}=ylnx=y
{4}^{x}=\ln{\frac{11}{5}}4x=ln511
: {b}^{a}=xba=x if and only if log_b(x)=alogb(x)=a
x=\log_{4}{\ln{\frac{11}{5}}}x=log4ln511
Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}logbx=logablogax
x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=log4logln511
Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}logbxc=clogbx
\log{4}log4 -> \log{{2}^{2}}log22 -> 2\log{2}2log2
x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=2log2
Answer= −0.171
