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Paraphin [41]
3 years ago
11

PLEASE HELP ASAP 25 PTS TO RIGHT/BEST ANSWER

Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0
Subtract 1111 from both sides

5{e}^{{4}^{x}}=22-115e​4​x​​​​=22−11


 

Simplify 22-1122−11 to 1111

5{e}^{{4}^{x}}=115e​4​x​​​​=11



 

Divide both sides by 55

{e}^{{4}^{x}}=\frac{11}{5}e​4​x​​​​=​5​​11​​



 

Use Definition of Natural Logarithm: {e}^{y}=xe​y​​=x if and only if \ln{x}=ylnx=y

{4}^{x}=\ln{\frac{11}{5}}4​x​​=ln​5​​11​​



 

: {b}^{a}=xb​a​​=x if and only if log_b(x)=alog​b​​(x)=a

x=\log_{4}{\ln{\frac{11}{5}}}x=log​4​​ln​5​​11​​



 

Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}log​b​​x=​log​a​​b​​log​a​​x​​

x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=​log4​​logln​5​​11​​​​



 

Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}log​b​​x​c​​=clog​b​​x
\log{4}log4 -> \log{{2}^{2}}log2​2​​ -> 2\log{2}2log2

x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=​2log2​


Answer= −0.171
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ICE Princess25 [194]

Answer:

30.4 feet.

Step-by-step explanation:

We have been given the length of the ramp on the blueprint is 7.6 inches.  The scale on the blueprint is 1 inch to 4 feet. We are asked to find the actual length of the ramp.

We will use proportions to solve our given problem as:

\frac{\text{Actual length}}{\text{Scale length}}=\frac{4\text{ ft}}{1\text{ inch}}

Now, we will substitute the scale length of ramp in our proportion as:

\frac{\text{Actual length}}{7.6 \text{ Inches}}=\frac{4\text{ ft}}{1\text{ inch}}

\frac{\text{Actual length}}{7.6 \text{ Inches}}\cdot 7.6 \text{ Inches}=\frac{4\text{ ft}}{1\text{ inch}}\cdot 7.6 \text{ Inches}

\text{Actual length}=4\text{ ft}\cdot 7.6

\text{Actual length}=30.4\text{ ft}

Therefore, the actual length of the ramp would be 30.4 feet.

7 0
3 years ago
Some one help me please
Lera25 [3.4K]
11662 - 20%= 9329.6 add sales tax 6 3/4 % or 6.75% =$9,959.348 or $9,9959.35
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3 years ago
Each square on the grid represents 1 ft2.
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