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IrinaVladis [17]
2 years ago
12

Isaac invested $460 in an account paying an interest rate of 2.4% compounded daily. Assuming no deposits or withdrawals are made

, how long would it take, to the nearest year, for the value of the account to reach $690?
Mathematics
2 answers:
allochka39001 [22]2 years ago
4 0

Answer:

t =17 years

Step-by-step explanation:

The formula for interest

A = P(1+ r/n)^ nt

where a is the amount in the account , p is the principal, r is the rate, n is the number of times compounded per year and t is the time in years

Substituting in what we know

690 = 460 ( 1+ .024/365)^ 365t

690/460 = ( 1+ .024/365)^ 365t

1.5 = ( 1+ .024/365)^ 365t

Taking the log of each side

log(1.5) = 365t log( 1+ .024/365))

Dividing each side by( 1+ .024/365)

log(1.5)/ log( 1+ .024/365) = 365t

divide each side by 365

1/365 log(1.5)/ log( 1+ .024/365)  =t

t =16.8949

To the nearest year

t =17

Advocard [28]2 years ago
3 0

Answer:

17 years

Step-by-step explanation:

460 (1 + (2.4/365)%)^t = 690

1.000065753425^t = 1.5

t ln1.000065753425 = ln1.5

t = 6,166.6535619036 days

6,166.6535619036/365

= 16.8949412655 years

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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is the solution to the inequality -3x-42>3 ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

- 3 x - 42 \gt 3

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Add 3 and 42 to get 45.

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