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galina1969 [7]
3 years ago
7

The mean for 1,2,3,4

Mathematics
1 answer:
worty [1.4K]3 years ago
6 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>:</em><em>)</em>

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Chose one value for x and substitute the value in the equation to get your answer pick x=15 or x=12 or x=10 2x+13
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If I pick 10, then 2(10)+13=33
If I pick 15, then 2(15)+13=43
If I pick 12, then 2(12)+13=37
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What is 3/8 x 3/8 x 3/8 written as a power
julia-pushkina [17]

Answer:

3/8^3

Step-by-step explanation:

its like 1/2 x 1/2 x1/2 its 1/2^3

or  7x7x7x7x7=7^5 its the same concept....

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The antlantic ocean region contains approximately 2 times 10^16 gallons of water. Lake Ontario has approximately 8,000,000,000,0
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Jared has 4 less than 3 times the number of trophies that zach had.
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The resting heart rate of 60 patients is shown in the frequency table below.
Murrr4er [49]

The standard deviation is 9.27. The typical heart rate for the data set varies from the mean by an average of 9.27 beats per minute.

<h3>How to determine the standard deviation of the data set?</h3>

The dataset is given as:

Heart Rate  Frequency

60 1

65 3

70 4

75 12

80 8

85 15

90 9

95 5

100 3

Calculate the mean using

Mean = Sum/Count

So, we have

Mean = (60 * 1 + 65 * 3 + 70 * 4 + 75 * 12 +  80 * 8 +  85 * 15 +  90 * 9 +  95 * 5 + 100 * 3)/(1 + 3 + 4 + 12 + 8 + 15 + 9 + 5 + 3)

Evaluate

Mean = 82.25

The standard deviation is

\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f -1}}

So, we have:

SD = √[1 * (60 - 82.25)^2 + 3 * (65 - 82.25)^2 + 4 * (70 - 82.25)^2 + 12 * (75 - 82.25)^2 + 8 * (80 - 82.25)^2 +  15 * (85 - 82.25)^2 +  9 * (90  - 82.25)^2 + 5 * (95 - 82.25)^2 + 3 * (100 - 82.25)^2)]/[(1 + 3 + 4 + 12 + 8 + 15 + 9 + 5 + 3 - 1)]

This gives

SD = √85.9533898305

Evaluate

SD = 9.27

Hence. the standard deviation is 9.27. The typical heart rate for the data set varies from the mean by an average of 9.27 beats per minute.

Read more about standard deviation at:

brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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