You are given two equations, solve for one variable in one of the equations. Say you solved for x in the second equation. Then, plug in that value of x in the x of the first equation. Solve this (first) equation for y (as it should become apparent) and you'll get a number value. Plug in this numerical value of y into the y of the second equation. Solve for x in the second equation. And there you have it: (x, y)
Answer:
x = 1091.63315843
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Setting Up:
7 = ln ( x + 5 )
ln translates to "log" with an "e" as the base or subscript ( a small "e" at the bottom right of the "g" in log).
You take the base of the log and put it to the power of "7" ( "7" is the natural log of ( x + 5 ) in this problem ).
The value of which the logarithm is calculated is set equal to the base of the logarithm to the power of the calculated logarithm of the value.
e^7 = x + 5
Solving</span>:
e = 2.71828182846
Natural logarithms are logarithms to the base of the constant 'e'.
e^7 = x + 5 ( simplify e^7 )
<span>1096.63315843 = x + 5
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Subtract 5 from each side.
1091.63315843 = x
Answer:
The two lines are not parallel.
Step-by-step explanation:
Every linear equation follows this structure:
y = mx + b
y is the y value
x is the x value
m is the gradient/slope of the line
b (or sometimes c) is the y-intercept of the line
Firstly, we have to get the y term on one side by itself.
6x + y = -1
-6x -6x
y = -6x - 1
-2x -5y = 1
+2x +2x
-5y = 2x + 1
Secondly, we make it so the y term is just the y value.
The first equation is already like this, so we don't need to do anything to that.
-5y = 2x + 1
÷ -5 ÷ -5
y = (2x + 1) / -5
This can be expanded and simplified to:
y = -2/5x - 1/5
Thirdly, we have to compare the slopes and y-intercepts.
y = -6x - 1
y = 2/5x - 1/5
If the slopes are the same and the y-intercepts are different, they are parallel. However, the slopes are different, therefore they are not parallel.
Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
