Answer:
The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>
Step-by-step explanation:
Given:
Helicopter flies 10 miles east of bristol.
Then the helicopter flies 8 miles North before landing.
To find the direct distance between the helicopter and bristol.
Solution:
In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter
The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.
On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.
Applying Pythagorean theorem to find the hypotenuse of the triangle.
Taking square root both sides.
Thus, the distance of the helicopter from the bristol is approximately 12.81 miles
Answer:
the answer is d
<em>The square root property should have been applied to both complete sides of the equation instead of to select variables.
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Step-by-step explanation: i just took the test on edge
The first thing we should do is see what relationship we have:
Table is feet to yards 3-1
a. Describe the relationship between the number of feet and the number of yards
That is to say:
1Yarda = 3 feet
b. Write an expression for the number of yards in f feet
Let
y = Yard
f = feet
We have the following expression for the conversion:
y = (1/3) f
c. Find the number of yards in 63 feet
For this case we must substitute in the expression found the value of f = 63.
y = (1/3) f
y = (1/3) (63)
y = 21
answer:
1Yarda = 3 feet
y = (1/3) f
y = 21
Easy, that is the slope from (2,f(2)) to (3,f(3))
remember that the slope between the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
find f(2) and f(3)
f(2)=2²+6(2)+5=4+12+5=21
f(3)=3²+6(3)+5=9+18+5=32
so the slope from (2,21) to (3,32) is (32-21)/(3-2)=11/1=11
answer is 11
Answer: tan62 = 10/x
Step-by-step explanation: Let me know if you need an explanation.
