Erica can run 1/6 of a kilometer her school is 3/4 of a kilometer away from her home at this this speed how long would it take e
1 answer:
Answer:
4 minutes 30 seconds
Step-by-step explanation:
Given:
Erica can run 1/6 of a kilometer in one minute.
Her school is 3/4 of a kilometer away from her home.
Question asked:
How long would it take Erica to run home from school = ?
Solution:
As here distance is given and also speed is given, we will find time taken to run from home to school by using,
Therefore, it takes 4 minutes 30 seconds Erica to run home from school.
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NOTES:
Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:
- if "a" is positive, then opens UP
- if "a" is negative, then opens DOWN
Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:
- the Axis Of Symmetry (x-value) is: x =
- y-value is found by plugging in the AOS for "x" in the equation
****************************************************************************************
1) y = x² + 11x + 24
- a = +1 so the parabola opens UP
- x =
=
=
- y =
+ 11
+ 24 =
- vertex
,
is in Quadrant 3 and is below the x-axis
This COULD be the graph of the rain gauge.
The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)
******************************************************************************************
2) y = -x² - 6x - 8
- a = -1 so the parabola opens DOWN
- x =
=
= -3
- y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1
- vertex (-3, 1) is in Quadrant 2 and is above the x-axis
This could NOT be the graph of the rain gauge.
The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)
******************************************************************************************
3) y = x² - 2x + 3
- a = 1 so the parabola opens UP
- x =
=
= 1
- y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2
- vertex (1, 2) is in Quadrant 1 and is above the x-axis
This could NOT be the graph of the rain gauge.
The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). <em>There are no x-intercepts</em>
******************************************************************************************
4) y = x² + 4x + 4
- a = 1 so the parabola opens UP
- x =
= -2
- y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0
- vertex (-2, 0) is in Quadrant 2 and is on the x-axis
This COULD be the graph of the rain gauge.
The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). <em>The x-intercept is the vertex.</em>
Compared to the other four graphs, this is most likely the equation for the rain gauge!
******************************************************************************************
5) y = 3x² + 21x + 30
- a = +3 so the parabola opens UP
- x =
=
- y = 3
+ 21
+ 30 =
- vertex
,
is in Quadrant 3 and is below the x-axis
This COULD be the graph of the rain gauge.
The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)
*******************************************************************************************