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Sonja [21]
4 years ago
13

Describe how to transform (^6sqrtx^5)^7 into an expression with a rational exponent.

Mathematics
2 answers:
nirvana33 [79]4 years ago
8 0
\left( \sqrt[6]{x^5} \right)^7 =\left( x^{ \frac{5}{6} } \right)^7 =x^{ \frac{35}{6} }
Schach [20]4 years ago
6 0
Hmmm did you mean   \huge \bf \sqrt[6]{(\sqrt{x^5})^7} ?
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Write the standard form of the line that passes through the given points. Inclide your work in the final answer. Type your answe
ANTONII [103]

Answer:

y=7

Step-by-step explanation:

Slope: 7-7/4-0=0

Point: (0,7)

pt/slope form:

y-7=(0)(x-0)

y=7

8 0
3 years ago
Kerille is reading a book at the rate of 4.5 pages per minute. What ordered pair on a graph of his reading rate would represent
viva [34]
This is a linear equation y = mx, where:
m= slope or reading rate:
x = the number of minutes
y = the number of pages read.

So the equation becomes: y = 4.5.x
How many minutes it will take to read 90 pages (y):
90 = 4.5.x    or x = 90/4.5  and x = 20 minutes
So the ordered pair will be (20,90)



5 0
4 years ago
What is the solution set for 9x2-25=0
Alexandra [31]

Answer: i hope i helped if not im truly sorry

Solving for 9x^2 - 25 = 0

Standard form:

9x2 − 25 = 0

Solutions based on quadratic formula:

x1  

= −0 − √ 02 − 4×9×(−25)  

2×9

= 0 − 30 × √ 1  

18

≈ −1.667

x2  

= −0 + √ 02 − 4×9×(−25)  

2×9

= 0 + 30 × √ 1  

18

≈ 1.667

Extrema:

Min = (0, −25)

Step-by-step explanation: im not dumb and im not smart

4 0
3 years ago
Do the side lengths 9,12,15 classify as a right,acute,obtuse triangle, or “no possible triangle”
HACTEHA [7]
Refer to c^2=a^2+b^2 (^2 means squared)
C is the hypotenuse and will be the longest measure
So 15^2= 9^2+12^2
225=225
If both sides are equal then the triangle is a right triangle, if the hypotenuse (or c) is lower or higher than you can determine whether it’s obtuse or acute
It would be a right triangle
6 0
3 years ago
Question in screenshot answer must be in cm
prisoha [69]

Answer:

30.5 cm

Step-by-step explanation:

0 < h ≤ 10 ⇔ Midpoint = 5

10 < h ≤ 20 ⇔ Midpoint = 15

20 < h ≤ 30 ⇔ Midpoint = 25

30 < h ≤ 40 ⇔ Midpoint = 35

40 < h ≤ 50 ⇔ Midpoint = 45

50 < h ≤ 60 ⇔ Midpoint = 55

<u>⇒ </u><u><em>Multiply each corresponding midpoint with it's frequency</em></u>

(5 × 1) + (15 × 4) + (25 × 7) + (35 × 2) + (45 × 3) + (55 × 3) = 610

<u>⇒ </u><u><em>Divide the total of 610 by the frequencies added together</em></u>

610 ÷ (1 + 4 + 7 + 2 + 3 + 3) = 610 ÷ 20 = 30.5

8 0
3 years ago
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