Describe how to transform (^6sqrtx^5)^7 into an expression with a rational exponent.
2 answers:
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Answer: The equation of the parabola is .
Explanation:
It is given that the focus of the parabola is (-5,-5) and the directrix is y=7.
The standard form of the parabola is,
Where y=k-p is directrix and (h,k+p) is the focus.
Since focus is given,
On comparing,
.... (1)
The directrix is y=7.
.... (2)
Add equation (1) and (2),
Put this value in (1).
Put p= -6, h= -5 and k=1 in the standard form of the parabola.
Therefore, the equation of parabola is .
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is