Answer:
Step-by-step explanation:
![\sqrt[3]{2x^5y^7} * \sqrt[3]{4x^4y^2} \\\\2x^3y^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%5E5y%5E7%7D%20%2A%20%5Csqrt%5B3%5D%7B4x%5E4y%5E2%7D%20%5C%5C%5C%5C2x%5E3y%5E3)
Hello!
All you have to do it divide 5280 ft by 9 min to find ft/min:
5280 / 9 = 506.67 ft/min
I hope this helps :))
Step-by-step explanation:
Let's say R is the initial radius of the sphere, and r is the radius at time t.
The volume of the sphere at time t is:
V = 4/3 π r³
Taking derivative with respect to radius:
dV/dr = 4π r²
This is a maximum when r is a maximum, which is when r = R.
(dV/dr)max = 4π R²
This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.
C, 16cm. Count along the edges for the number of lines.
