7x ( x + 1.8 ) = 0 → x = 0 or x = -1.8
<h3>Further explanation</h3>
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :
<h2>D = b² - 4 a c</h2>
From the value of Discriminant , we know how many solutions the equation has by condition :
D < 0 → No Real Roots
D = 0 → One Real Root
D > 0 → Two Real Roots
Let us now tackle the problem!
<u>Given :</u>
![7x ( x + 1.8 ) = 0](https://tex.z-dn.net/?f=7x%20%28%20x%20%2B%201.8%20%29%20%3D%200)
<u>Solution :</u>
![(7x )( x + 1.8 ) = 0](https://tex.z-dn.net/?f=%287x%20%29%28%20x%20%2B%201.8%20%29%20%3D%200)
![(7x) = 0 \texttt{ or } (x + 1.8) = 0](https://tex.z-dn.net/?f=%287x%29%20%3D%200%20%5Ctexttt%7B%20or%20%7D%20%28x%20%2B%201.8%29%20%3D%200)
![x = 0 \div 7 \texttt{ or } x = 0 - 1.8](https://tex.z-dn.net/?f=x%20%3D%200%20%5Cdiv%207%20%5Ctexttt%7B%20or%20%7D%20x%20%3D%200%20-%201.8)
![x = 0 \texttt{ or } x = - 1.8](https://tex.z-dn.net/?f=x%20%3D%200%20%5Ctexttt%7B%20or%20%7D%20x%20%3D%20-%201.8)
<h3>Therefore, the solution is x = { 0 , -1.8 }</h3>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Quadratic Equations
Keywords: Quadratic , Equation , Discriminant , Real , Number , Solution , Zero , Root
#include
int main()
{
int num;
scanf("%d", &num);
printf("%d", num*num);
return 0;
}
Answer:
5/21
Step-by-step explanation:
2/7 * 5/6 = 2 * 5 / 7 * 6 = 10 / 42 = 5/21
Answer:
Can I have brainliest now
Step-by-step explanation:
just answered your help message