I suppose <em>K</em> is the matrix
![K = \begin{bmatrix}14 & -13 & 0 \\ 3 & 8 & -1 \\ -10 & -2 & 5\end{bmatrix}](https://tex.z-dn.net/?f=K%20%3D%20%5Cbegin%7Bbmatrix%7D14%20%26%20-13%20%26%200%20%5C%5C%203%20%26%208%20%26%20-1%20%5C%5C%20-10%20%26%20-2%20%26%205%5Cend%7Bbmatrix%7D)
To compute det(<em>K</em>), you can use a simple cofactor expansion along the first row:
![\det(K) = 14\times\det\begin{bmatrix}8 & -1 \\-2 & 5\end{bmatrix} - (-13)\times\det\begin{bmatrix}3 & -1 \\ -10 & 5\end{bmatrix} + 0\times\det\begin{bmatrix}3 & 8 \\ -10 & -2\end{bmatrix} \\\\ \det(K) = 14\times(8\times5-(-1)\times(-2)) + 13\times(3\times5-(-1)\times(-10)) + 0 \\\\ \det(K) = 14\times38 + 13\times5 = \boxed{597}](https://tex.z-dn.net/?f=%5Cdet%28K%29%20%3D%2014%5Ctimes%5Cdet%5Cbegin%7Bbmatrix%7D8%20%26%20-1%20%5C%5C-2%20%26%205%5Cend%7Bbmatrix%7D%20-%20%28-13%29%5Ctimes%5Cdet%5Cbegin%7Bbmatrix%7D3%20%26%20-1%20%5C%5C%20-10%20%26%205%5Cend%7Bbmatrix%7D%20%2B%200%5Ctimes%5Cdet%5Cbegin%7Bbmatrix%7D3%20%26%208%20%5C%5C%20-10%20%26%20-2%5Cend%7Bbmatrix%7D%20%5C%5C%5C%5C%20%5Cdet%28K%29%20%3D%2014%5Ctimes%288%5Ctimes5-%28-1%29%5Ctimes%28-2%29%29%20%2B%2013%5Ctimes%283%5Ctimes5-%28-1%29%5Ctimes%28-10%29%29%20%2B%200%20%5C%5C%5C%5C%20%5Cdet%28K%29%20%3D%2014%5Ctimes38%20%2B%2013%5Ctimes5%20%3D%20%5Cboxed%7B597%7D)
Answer:
find the value of the inequality on the number line
Step-by-step explanation:
do open circle for greater or less than
do closed circle for equal to
draw line left or right based on greater or less than
Answer:
Answer:
Domain is
All real number except at x=0
Step-by-step explanation:
We are given
Firstly, we will find (fog)(x)
now, we can plug back g(x)
Domain:
we know that domain is all possible values of x for which any function is defined
and we know that denominator of any function can not be zero
so, we set denominator =0
so, function will be defined for all values of x except at x=0
So, domain will be
All real number except at x=0
Hope this helps!
Answer:
fog=18x^2 -48x+32
Step-by-step explanation: