In which quadrant is the number 6 – 8i located on the complex plane?
2 answers:
Answer:
A complex number Z = A + Bi can be represented in the same way like we represent a point (a,b) in the coordinate plane.
Like in two dimensional coordinate system where there is X axis and Y Axis In complex plane , for locating real part of complex number we use X axis and for locating imaginary part we use Y axis.
So Complex number Z= 6 - 8 i = Point in the complex plane (6,-8)
6 = Real Part = Positive real number
-8 = Imaginary Part = Negative real number
Point (6,-8) will lie in Fourth Quadrant.
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Answer:
a = 4, x = 1
Step-by-step explanation:
The opposite sides of a parallelogram are congruent , then
WX = YZ , that is
a² + 5a = 5a + 16 ( subtract 5a from both sides )
a² = 16 ( take the square root of both sides )
a = ± = ± 4
Since a > 0 , then a = 4
Also
XY = WZ , that is
x² + 6x = 4x + 3 ( subtract 4x + 3 from both sides )
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Since x > 0 , then x = 1