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Monica [59]
3 years ago
10

Person A can paint the​ neighbor's house 3 times as fast as Person B. The year A and B worked​ together, it took them 10 days. H

ow long would it take each to paint the​ house?
Bro I don't know if I'm dumb or not but I literally can't figure this out. Please help my struggling self wcdfvrd
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

  • A: 13 1/3 days
  • B: 40 days

Step-by-step explanation:

If person A can paint the house in 'a' days, then person B takes 3a days. Each day, the total amount of house painted when they work together is ...

  1/a + 1/(3a) = 1/10

  4/(3a) = 1/10 . . . combine terms

  40 = 3a . . . . . . . cross multiply

  a = 40/3 = 13 1/3 . . . . . divide by 3

A can paint the house in 13 1/3 days.

B can paint the house in 40 days.

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Answer:

12 seconds.

Step-by-step explanation:

If you put it like 15/9 = 20/x, then cross multiply and divide you do 9 times 20 you get 180, then you divide 180 by 15 and you get 12. Hope this helps!

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Let f(x)=100−10+e−0.1x .
lianna [129]
What are you solving for?
If you are solving for × then I hope this helps

Let's solve for x.

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Step 1: Add 0.1x to both sides.

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Step 2: Factor out variable x.

x(f+0.1) = e+90

Step 3: Divide both sides by f+0.1.

x(f+0.1)/ f+0.1 =e+90/ f+0.1

x=e+90/ f+0.1

Answer:

x= e+90/ f+0.1
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