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Monica [59]
4 years ago
10

Person A can paint the​ neighbor's house 3 times as fast as Person B. The year A and B worked​ together, it took them 10 days. H

ow long would it take each to paint the​ house?
Bro I don't know if I'm dumb or not but I literally can't figure this out. Please help my struggling self wcdfvrd
Mathematics
1 answer:
Angelina_Jolie [31]4 years ago
3 0

Answer:

  • A: 13 1/3 days
  • B: 40 days

Step-by-step explanation:

If person A can paint the house in 'a' days, then person B takes 3a days. Each day, the total amount of house painted when they work together is ...

  1/a + 1/(3a) = 1/10

  4/(3a) = 1/10 . . . combine terms

  40 = 3a . . . . . . . cross multiply

  a = 40/3 = 13 1/3 . . . . . divide by 3

A can paint the house in 13 1/3 days.

B can paint the house in 40 days.

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3 years ago
In the game of roulette, a wheel consists of 32 slots numbered 00, 0, 1, 2, . . . , 30. To play the game, a metal ball is spun a
Zarrin [17]

Answer:

(a) The sample space is {00, 0, 1, 2, . . . , 30}.

(b) If the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3.

(c) If the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.

Step-by-step explanation:

We are given that in the game of roulette, a wheel consists of 32 slots numbered 00, 0, 1, 2, . . . , 30.

To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots.

(a) The sample space is {00, 0, 1, 2, . . . , 30} which means the metal ball can land on any of these numbers.

(b) As we know that there is an equal probability of the metal ball landing on any of the slots marked in the sample space.

Total number of slots = 32

Number of slots marked with 3 = 1

So, the probability that the metal ball falls into the slot marked 3 is given by =  \frac{1}{32}  = 0.031 or 3.1%

This means that if the wheel is spun 100 times, it is expected about 3.1 of those times to result in the ball landing in slot 3.

So, if the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3 because (0.031 \times 1000) = 31.

(c) As we know that the odd slot in the given sample space is {1, 3, 5,......, 29}.

Total number of slots = 32

Number of odd slots = 15

So, the probability that the metal ball lands in an odd slot is given by =  \frac{15}{32}  = 0.47 or 47%.

This means that if the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.

6 0
3 years ago
How do I do 7 divided by 1/3
rewona [7]

7÷ 1/3

KCF---Keep->Change->Flip

7/1 × 3/1 = 21/1==21

5 0
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The vending machine in the school cafeteria usually dispenses about 6 ounces of soft drink. Lately, it is not working properly,
masya89 [10]
#1) D, 95%
#2) B, 34%

Explanation
#1) The mean is 6 and the standard deviation is 0.2.  5.6 is 0.4 away from the mean; 0.4 is 2 standard deviations.  6.4 is 0.4 away from the mean; again, 0.4 is 2 standard deviations.

The empirical rule states that 95% of data will be within 2 standard deviations of the mean, so 95% is our answer.

#2) 6.2 is only 1 standard deviation away from the mean.  However, this is only half of the percentage from the empirical rule, since we are only considering numbers larger than the mean.  The empirical rule states that 68% of data will fall within 1 standard deviation from the mean, so we have
68/2 = 34%.
6 0
4 years ago
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