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3 years ago

Which inequality is represented by this graph? 0 - 345> x O 0 -34.5 0 -355 cx

Mathematics

1 answer:

julia-pushkina [17]3 years ago

8 0

Answer:

Step-by-step explanation:

If x is the white dot on the graph:

From what it looks like, x is right between -35 and -34 x (which is -35.5).

If that is the case then none of the answers are correct since -35.5 is <u>equal or less</u> than x. (the sign looks like this: " $\leq$ " )

But if you have to choose one of the answers then number 4 (-35.5 < x) would be closest.

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PLEASE HELP(Need answer now)

valentina_108 [34]

Answer:

x=74

Step-by-step explanation:

180-106=74

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3 years ago

Last weekend 270 movie tickets were sold. This weekend 216 tickets were sold.

andreev551 [17]

Answer:

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Step-by-step explanation:

270- 216 = 54

so ...the percentage becomes

54/270 × 100 = 20%

7 0

4 years ago

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

Please help me every one!!! Please and thank you if you you did it :)

Vesnalui [34]

Answer: look in explenation

Step-by-step explanation:

ok so u go to snap, open the filters, on the bottom it says scan, click in that and find the calculator feature. scan all ur equations with it one by one, and boom

8 0

3 years ago

mr carlos buys 1,080 apples. 1/9 of the apples are rotten. he sells the rest at $2 for 10 apples. how much does he earn from the

Nataliya [291]

$\frac{1}{9}\cdot 1080=120\\1080-120=960\\960:10=96\\96 \cdot \$2=\$192\\\\Answer:Mr\ Carlos\ will\ earn\ \$192\ for\ the\ sale.$

3 0

4 years ago

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Which inequality is represented by this graph? 0 - 345> x O 0 -34.5 0 -355 cx​

Which inequality is represented by this graph? 0 - 345> x O 0 -34.5 0 -355 cx