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Varvara68 [4.7K]
3 years ago
13

z varies directly with x and inversely with y^2. When x = 2 and y = 5, z = 8. What is the value of z when x = 4 and y = 9?

Mathematics
2 answers:
Ivanshal [37]3 years ago
4 0
Direct variation is  y = kx

Inverse variation is y = k/y

if z varies directly with x, then the equation would be z = kx

if z varies inversely with y^2 then the equation would be z = k/y^2. Combining, these two, we have z = kx/y^2

We use the first set of values to find the constant k:

x = 2, y = 5, z = 8:

8 = 2x/25, k = 100. Now we use the second set of values to find z:

x = 4, y = 9, k = 100 and z is unknown:

z = (4X100)/9^2

z = 400/81--> this is your final final answer.

*plz rate brainliest
Kaylis [27]3 years ago
3 0

The Answer is definitely..

400/81

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5(3m+2)<br> 6(g+h)<br> 4d+8<br> 21p+35q<br> 18x+9y
aalyn [17]
<span>(a) 5(3m+2) = 15m + 10

(b) 6(g+h) = 6g + 6h

(c) 4d+8 = 4(d + 2)

(d) 21p+35q = 7(3p + 5q)

(e) 18x+9y = 9(2x + y)</span>
7 0
3 years ago
If AB vector =(4 5) and PQ vector=(2p 10) are parallel to each other, find the value of p.​
Sedaia [141]

Answer:

Answer:

They both have q+3/2p, so that means that 2PQ=CB and that means they are parallel to each other

Step-by-step explanation:

PQ=PA+QA

PQ=1/2(2q-p)+2/5*5p=q-1/2p+2p=q+3/2p

CB=2q+3p=2(q+3/2p)

Other explanation: It should be written like this PQ=q+3/2p and CB=2q+3p=2(q+3/2p) they are parallel bcs CB=2*PQ.

8 0
3 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
the graph of liner function f passes through the point (1,-9) ad has a slope of -3 what is the zero of f
Lostsunrise [7]

Answer:

answer 4 im pretty sure

Step-by-step explanation:

i did da math

8 0
2 years ago
What is |x|/-6=12 a no solution b -2or 2 c -72or72 d 72. im really confused
Kobotan [32]
Remember
|x|≥0 for every real value of x

so

|x|/-6=12
divide both sideds by -6
|x|=-2
false, the absolut value cannot be negatve
6 0
3 years ago
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