Answer:
100.5cm2
Step-by-step explanation:
v=pi(r)2(h)
v=3.14(2)2(8)
v=3.14(4)(8)
v=100.48
v=100.5cm2
Answer:
To produce 400 gallons of a chemical, it costs 700 dollars.
Step-by-step explanation:
We have that:
The cost, C (in dollars) to produce g gallons of a chemical can be expressed as C=f(g).
The interpretation is:
To produce g gallons of a chemical it costs C dollars.
So
f(400)=700
This means that to produce 400 gallons of a chemical, it costs 700 dollars.
<span>Given number is 41/50,
Now, let’s find which one is closer to the given choices:
=> 9/11
=> 10/11
Notice that the given number and given choices are fraction numbers. In order
know which one is closer to the given number, we need to convert these numbers
into a decimal.
Note, that in converting a fraction number to a decimal is we need to divide
our numerator by our denominator to get the answer.
=> 41/50
=> 0.82
The value of 41/50 is 0.82. Now, let’s find the value of the given choices.
=> 9/11
=> 0.818 or 0.82
=> 10/11
=>0.909 or 0.91
Thus, the correct answer is 9/11 is equals to 41/50.</span>
Answer:
0.4 pounds
Step-by-step explanation:
10 pounds / 25 square feet
to get the number of pounds per feet
10 / 25 = 0.4
so, your answer is 0.4 pounds per 1 square foot
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
