Question

Quadrilateral ABCD is drawn on a coordinate plane. Find the length of the side AB. Please help

Answer 1

Answer:

B. /AB/  =  $\sqrt{45}$ units

Step-by-step explanation:

A quadrilateral is the class of four sided figures. Examples include: squares, rectangles, rhombus, kite, parallelogram, trapezium etc.

From the graph, the quadrilateral is in the form of a trapezium.

the length of the side AB can be determined by:

Draw a perpendicular from B to meet AD at E to form triangle ABE,

From triangle ABE, AE = 3 units and BE = 6 units. Applying the Pythagoras theorem to determine the length AB, we have;

  $/AB/^{2}$ = $/BE/^{2}$ + $/AE/^{2}$

             = $6^{2}$ + $3^{2}$

             =  36 + 9

$/AB/^{2}$    = 45

Find the square root of both sides,

   /AB/  =  $\sqrt{45}$

Thus,

/AB/  =  $\sqrt{45}$ units

Answer 2

Hello from MrBillDoesMath!

Answer:

sqrt(45)

Discussion:

See the attached file. The length AB is the hypotenuse of  the right triangle with sides 3 and 6. Hence

AB = sqrt ( 3^2 + 6^2)

     = sqrt ( 9 + 36 )

    = sqrt (45)                <----- this is the answer they wanted!

    = sqrt (9 *5)

    = sqrt(9) * sqrt(5)

    = 3 * sqrt(5)

Thank you,

MrB