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3 years ago

Evaluate 3+11t -9u when t=9 u =11

Mathematics

2 answers:

Triss [41]3 years ago

5 0

ANSWER

$3$

EXPLANATION

The given expression is

$3+11t-9u$

The question demands that, we find the value of the given expression when

$t = 9 \: and \: u = 11$

This is a substitution problem, so we substitute the given values to obtain,

$3+11(9)-9(11)$

This simplifies to,

$= 3+99-99$

We evaluate to obtain,

$= 3 + 0$

This will finally give us,

$= 3$

Tanya [424]3 years ago

4 0

Its too easy to do ......
hope this helps u.....

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True or false.

bearhunter [10]

The answer for the given question above is FALSE.
Fifth root if 12 is equal to 1.64375183
Fifth root of 7 is equal to 1.47577316
Fifth root of 5 is equal to 1.37972966

1.47577316 times 1.37972966 = 2.0361680003

6 0

4 years ago

Which t-chart represents the absolute value equation y = |5x|?

Crank

<h3>Answer: Choice C</h3>

=============================================

Explanation:

Choices A, B and D are not true because of the negative y values. The result of an absolute value is never negative. So we can rule out choices A, B, and D. We have choice C as the only thing left, so this must be the answer.

-------------

Another way to see this is by plugging in each x value to see what y value comes out.

If x = -2, then y = |5*x| = |5*(-2)| = |-10| = 10
If x = -1, then y = |5*x| = |5*(-1)| = |-5| = 5
If x = 0, then y = |5*x| = |5*0| = |0| = 0
If x = 1, then y = |5*x| = |5*1| = |5| = 5
If x = 2, then y = |5*x| = |5*2| = |10| = 10

The y outputs from top to bottom are: 10, 5, 0, 5, 10

This matches with what choice C shows.

5 0

4 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra

Rainbow [258]

Answer:

$x = t$

$y = 1 - t$

$z = 2t$

Step-by-step explanation:

Given

$x=t$

$y=e^{-t}$

$z=2t-t^2$

(0, 1, 0)

The vector equation is given as:

$r(t) = (x,y,z)$

Substitute values for x, y and z

$r(t) = (t,\ e^{-t},\ 2t - t^2)$

Differentiate:

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

The parametric value that corresponds to (0, 1, 0) is:

$t = 0$

Substitute 0 for t in r'(t)

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

$r'(0) = (1,\ -e^{-0},\ 2 - 2*0)$

$r'(0) = (1,\ -1,\ 2 - 0)$

$r'(0) = (1,\ -1,\ 2)$

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

$r(t) = a + tv$

Such that:

$a = (0,1,0)$ and $v = r'(0) = (1,-1,2)$

The equation becomes:

$r(t) = (0,1,0) + t(1,-1,2)$

$r(t) = (0,1,0) + (t,-t,2t)$

$r(t) = (0+t,1-t,0+2t)$

$r(t) = (t,1-t,2t)$

By comparison:

$r(t) = (x,y,z)$ and $r(t) = (t,1-t,2t)$

The parametric equations for the tangent line are:

$x = t$

$y = 1 - t$

$z = 2t$

7 0

3 years ago

Which of these trends represents an inverse variation?

BaLLatris [955]

I think it is the first one could be wrong tho

8 0

3 years ago

30 points.. Please Help! I don't understand what to do with this question...a bit confused.

Romashka-Z-Leto [24]

Eh, here's my best try for a table:

Like tv don't like tv total
Like reading: 70 10 80
Don't like read. 20 30 50 
total 90 40 130

The percentage of students that like tv as well as reading is- 70 divided by 130 which gives you .538 which in percentage is 53.8%.

The probability of a student that does not prefer to watch tv as also does not like to spend their time reading is 30 over 40 which can be simplified or reduced to 3 over 4. [30/40 reduced to 3/4]

Hope this somehow helped you :)

5 0

3 years ago