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3 years ago

11

I need help on my technical mathematics problems! ASAP

1 answer:

aliina [53]3 years ago

5 0

Cos <span>θ = 0.5333
inverse cosine both sides of equation
cos⁻¹(cos </span>θ) = cos⁻¹(0.5333)
on left side, cosine cancel out
on right side use calculator in radian mode
θ = 1.0083

for the ttriangle, assuming c is the hypotenuse
pythagoras
a² + b² = c²
b² = c² - a²
b = √(c² - a²)
b = √(9² - 2²)
b = 8.77

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Oduvanchick [21]

Given:

In triangle ABC, m∠A=(8x-2)°, m∠B=(2x-8)° and m∠C=(94-4x)°.

To find:

The sides of the triangle ABC in order from shortest to longest.

Solution:

In triangle ABC,

$m\angle A+m\angle B+m\angle C=180^\circ$ (Angle sum property)

$(8x-2)^\circ+(2x-8)^\circ+(94-4x)^\circ=180^\circ$

$(6x+84)^\circ=180^\circ$

$6x+84=180$

$6x=180-84$

$6x=96$

Divide both sides by 6.

$x=\dfrac{96}{6}$

$x=16$

Now,

$m\angle A=(8(16)-2)^\circ$

$m\angle A=(128-2)^\circ$

$m\angle A=126^\circ$

Similarly,

$m\angle B=(2(16)-8)^\circ$

$m\angle B=(32-8)^\circ$

$m\angle B=24^\circ$

And,

$m\angle C=(94-4(16))^\circ$

$m\angle C=(94-64)^\circ$

$m\angle C=30^\circ$

In a triangle the smaller angle has shorter opposite side and larger angle has longer opposite side.

$24^\circ$

$m\angle B$

$AC$

List the sides of triangle ABC in order from shortest to longest is AC:AB:BC.

Therefore, the correct option is A.

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