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MArishka [77]
3 years ago
11

Sandra flips a coin.what is the probability that the coin will land on tails?

Mathematics
2 answers:
Rama09 [41]3 years ago
8 0
The probability is 50/50
poizon [28]3 years ago
6 0
The probability would be 50%, or \frac{1}{2}, because there are only two possibilities when flipping a coin; either heads or tails. 
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How are expressions and equations different.
jeka57 [31]

Answer:

Equations are composed for many expressions.

Expressions can indicate variables, constants, etc.

Best regards

5 0
3 years ago
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harlie invests $325 in an account that pays 8% simple interest for 15 years. Use the simple interest formula, I = P ∙ r ∙ t, to
Alina [70]

$390 is the interest will Charlie’s initial investment earn over the 15-year period. The money does Charlie have after the 15 years is $715.

<u>Step-by-step explanation:</u>

Harlie invests $325 in an account.

  • Principal, P = $325
  • Interest rate, r = 8% ⇒ 0.08
  • Number of years, t = 15

<u>The formula to find the interest will Charlie’s initial investment earn over the 15-year period :</u>

⇒ I = Prt<u></u>

⇒ 325\times 0.08\times15

⇒ 390

Therefore, $390 is the interest will Charlie’s initial investment earn over the 15-year period.

<u>Money Charlie has after 15 years :</u>

It is given by the formula,

⇒ Amount = Principal + Interest.

⇒ 325 + 390

⇒ 715 dollars.

∴ The money does Charlie have after the 15 years is $715.

3 0
3 years ago
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To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
vlada-n [284]
<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
8 0
2 years ago
Random walk. A Java programmer begins walking aimlessly. At each time step, she takes one step in a random direction (either nor
ankoles [38]

Step-by-step explanation:

Hi, your question isn't totally complete. Here's the likely full question:

Random walk. A Java programmer begins walking aimlessly. At each time step, she takes one step in a random direction (either north, east, south, or west), each with probability 25%. She stops once she is at Manhattan distance r from the starting point. How many steps will the random walker take? This process is known as a two-dimensional random walk.

Write a program RandomWalker.java that takes an integer command-line argument r and simulates the motion of a random walk until the random walker is at Manhattan distance r from the starting point. Print the coordinates at each step of the walk (including the starting and ending points), treating the starting point as (0, 0). Also, print the total number of steps taken.

7 0
3 years ago
Bryan paid $136.00 for an item at the store that was 20% off the original price. What was the original price?
Dennis_Churaev [7]
The original price was $270.00
4 0
3 years ago
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