Explanation:
The below code has been written in C language
void rotateright(int list[], int n)
{
int x = list[n-1]
int i;
for (i = n-1; i > 0; i--)
list[i] = list[i-1];
list[0] = x;
}
void rotateleft(int list[], int n)
{
int x = list[0]
int i;
for (i = 1; i < n-1 ; i++)
list[i] = list[i+1];
list[n-1] = x;
}
int main()
{
int list[] = {x1, x2, x3, ... x(n-1),xn}
int i;
int n = sizeof(list);
rotateright(list, n);
rotateleft(list, n);
return 0;
}
Answer:
Option d pretest
Explanation:
Given the pseudocode:
- do stepA
- do stepB
- if conditionC is true
- then do stepD
- else
- do stepE
- end if
- while conditionF is true
- do stepG
- end while
The pseudocode above shows that there is a pretest before some codes are executed. For example, line 3 check if condition is true then only execute stepD otherwise execute stepE. Line 8 check if conditionF is true then repeatedly execute stepG. These are examples of pretest a condition will must be met (pretest passed) before a block of codes can be executed. This pretest can be seen in if-else statements and also the while condition.
Answer:
6=110
13=1101
18=10010
27=11011
Explanation:
A decimal number is converted to binary number by constantly dividing the decimal number by 2 till the number becomes zero and then write the remainders in reverse order of obtaining them.Then we will get our binary number.
I will provide you 1 example:-
18/2 = 9 the remainder =0
9/2 = 4 the remainder =1
4/2 = 2 the remainder =0
2/2 = 1 the remainder =0
1/2 = 0 the remainder =1
Writing the remainder in reverse order 10010 hence it is the binary equivalent of 18.
Explanation:
not A or D,
about B and C I'm not sure
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