Find a pattern for the sum of 4 times a number and twice the sum of the same number and 3
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Only 4 and 10 meet the requirements of the question.
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40 and 1 NOT, because 40 > 12
20 and 2 NOT, because 20 > 12
5 and 8 NOT because GCF(5, 8) = 1
Check the picture below.
using a second for it, since it's a horizontal line, then say hmmm we'll use the y-intercept, or (0, 1), so the equation of a line that passes through (2,1) and (0,1)
using a second for it, since it's a horizontal line, then say hmmm we'll use the y-intercept, or (0, 1), so the equation of a line that passes through (2,1) and (0,1)
a) <u>n² + 6 </u>
~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.
- If n = 1, first term = 1² + 6 = 7
- n = 2, second term = 10
- n = 3, third temm = 15
- n = 4, fourth term = 22
- n = 10, tenth term = 106
b) <u>3n²</u>
- If n = 1, first term = 3
- n = 2, second term = 12
- n = 3, third term = 27
- n = 4, fourth term = 48
- n = 10, tenth term = 300