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Vikentia [17]
3 years ago
12

Find a pattern for the sum of 4 times a number and twice the sum of the same number and 3

Mathematics
1 answer:
Minchanka [31]3 years ago
8 0
The answer is 4x + 2(x+3)
You might be interested in
Solving equations -3x+7=28?
AURORKA [14]

Answer:

x = - 7

Step-by-step explanation:

- 3x + 7 = 28

- 3x + 7 - 7 = 28 - 7

- 3x = 21

- 3x/3 = 21/3

- x = 7

x = - 7

3 0
3 years ago
Read 2 more answers
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
3 years ago
Help me I don't know what it is.
kotegsom [21]

Answer:

a is the correct answer

Step-by-step explanation:

-6-(-3)

-6+3

-3

8 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
What is 6,010,499,999 rounded to the nearest billion?
aleksandr82 [10.1K]

Answer:

6000000000

Step-by-step explanation:

Given the following question:

6,010,499,999

<u>Find the billions place value:
</u>

billions=6

<u>Round to the nearest billion:</u>
6,010,499,999
0
6000000000

Your answer is "6000000000."

Hope this helps.

3 0
2 years ago
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