Answer:
The quadratic equation in terms of v is v² + 2 v + 180 = 0
Step-by-step explanation:
Given as :
The distance between house to the school = d = 6 km
The uniform speed = v km/h
So, Time = 
or, t = 
Or, t = 
<u>Now, Again</u>
The speed is increase by 2 km/h
i.e speed = (v + 2) km/h
So, Time taken = t' = (t - 
)hours
i.e t' = (t - 
)hours
Now, Time =
So, (t - ) =
Or, (t - ) = 
Or , - =
Or , 
= 
Or, (90 - v) × (v + 2) = 6 × 15 v
Or, 90 v - 180 - v² - 2 v = 90 v
Or, v² + 2 v + 180 = 90 v - 90 v
Or, v² + 2 v + 180 = 0
So, The quadratic equation in terms of v
v² + 2 v + 180 = 0
Hence The quadratic equation in terms of v is v² + 2 v + 180 = 0 Answer
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Answer: 1/10=m, and b-3/10
Step-by-step explanation:
(s-3)/4+6
y=1/10s-3/10
For a line in the form of y=mx+b the slope is m and y-int is b.
1/10=m, and b-3/10
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤
