The number of students that were absent is; 24
<h3>How to find the Probability?</h3>
Let the total number of students be x .
The number of students which were absent = ¹/₃x.
Number of students which were present = ²/₃x
Thus;
Number of students who attended math's test = ¹/₂x
Number of students who attended physics test = ¹/₄x
No. of students who attended both tests = 6
A denotes number of students who attended math's test
B denotes number of students who attended physics test
Thus;
n(A) = ¹/₂x
n(B) = ¹/₄x
n(A ∩ B) = 6
n(A∪B) = number of students which were present
Thus;
n(A ∪ B) = n(A) + n(B) − n(A∩B)
²/₃x = ¹/₂x + ¹/₄x − 6
²/₃x = ³/₄x - 6
³/₄x - ²/₃x = 6
x = 72
Thus, number of students that were absent = ¹/₃ * 72
Number of students that were absent = 24
Read more about Probability at; brainly.com/question/251701
#SPJ1
Answer:
APart 1:
A.53 =53
B.3^5/3^-6 =177147
C.(1/4)^3 • (1/4)^2 = 1 /1024
D.(-7)^5/(-7)^7 = 1/49
Step-by-step explanation:
I tried my best for part 2 but i'm pretty sure it's not right. I think 1/1024 and 1/49 has a value between 0 and 1
As this rectangle has it's sides parallel to x axis and y axis
it is easy to find the length of it's sides by counting the number of blocks on each sides.
Let us first find co ordinates of all four points
we would calculate them left and right and up down direction from the origian ( the cross point of x and y axis )
A : it is 2 unit left 2 unit up ( -2 , +2 )
B is 5 unit right 2 unit up ( +5 ,+2)
C is 5 unit right 2 unit down ( +5,-2)
D is 2 unit left 2 unit down ( -2,-2)
Let us now find the distance AB : A is 2 unit left B is 5 unit right so length AB= 2+5 = 7
Let us now find distance AD : A is 2 unit up and D is 2 unit down
so length AD= 2+2= 4
Answer should be 7 x 4 units
Answer:
The couch is $778 and the table is $389
Step-by-step explanation:
