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sesenic [268]
3 years ago
7

We want to form a committee consisting of 3 men and 3 women, from a group of 8 women and 6 men. How many possible ways are there

to form the committee if:
Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

1120 possible ways

Step-by-step explanation:

In order to find the answer we need to be sure what equation we need to use.

From the given example, let's consider initially only men. Because you have a total of 8 men and we need to chose only 3 men, let's suppose that the 3 chosen men are A, B, and C.

Because A,B,C is the same as choosing C,B,A, which means it doesn't matter the order of the chosen men, we need to use a 'combination equation'.

Because we have two groups (women and men) then we have:

Possible ways = 8C3 * 6C3 (which are the combinations for women and men respectively). Remember that:

nCk=n!/((n-k)!*k!) so:

Possible ways = 8!/((8-3)!*3!) * 6!/((6-3)!*3!) = 56* 20 = 1120.

In conclusion, there are 1120 possible ways.

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Answer:

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Step-by-step explanation:

Step 1: We make the assumption that 35.5 is 100% since it is our output value.

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